## Algebra 1: Common Core (15th Edition)

Published by Prentice Hall

# Common Core End-of-Course Assessment - Page 797: 42

#### Answer

Answer choice $G$: $(3,0)$

#### Work Step by Step

In order to find out the solution for a system, make sure both equations are in $y=$ format. $y = x^2 + 2x-15$ $y = 4x - 12$ Solve the quadratic equation with $\frac{-b \pm \sqrt{b^2-4ac}}{2a}$. $a = 1$ $b = 2$ $c = -15$ $\frac{-2 \pm \sqrt{64}}{2}$. The solutions are $(3,0)$ and $(-5,0)$. When you plug these coordinates into the linear equation, $(3,0)$ is the only one that works. Therefore, the answer is $\boxed{G}$.

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