Chapter 9 - Quadratic Functions and Equations - 9-8 Systems of Linear and Quadratic Equations - Practice and Problem-Solving Exercises - Page 600: 29

$(-3,0),(-6,-3)$.

The given system is $-x^2-8x-15=y$ and $-x+y=3$ Graph each equation by using a graphing calculator. The points of intersection are $A=(-3,0)$ and $B=(-6,-3)$ Hence, the solutions are $(-3,0)$ and $(-6,-3)$.