Answer
$x=2.5$ or $x=0.1$
Work Step by Step
We are given:
$3x^2-8x=-1$
$3x^2-8x+1=0$
Use the quadratic formula.
$x=\frac{-(-8)+\sqrt (-8)^2-4.1.3}{2.3}$
$x=\frac{8 \pm 2\sqrt 13}{6}$
$x=\frac{4\pm \sqrt 13}{3}$
$x=\frac{4+ \sqrt 13}{3}$ or $x=\frac{4 - \sqrt 13}{3}$
$x=2.5$ or $x=0.1$