Answer
$(2x-1)(5x+2)$ are the factors of $10x^2-x-2$
Work Step by Step
We are given:
$10x^2-x-2$
$=10x^2-5x+4x-2$
$=5x(2x-1)+2(2x-1)$
$=(2x-1)(5x+2)$
$(2x-1)(5x+2)$ are the factors of $10x^2-x-2$
Algebra 1: Common Core (15th Edition)
by Charles, Randall I.
Published by
Prentice Hall
ISBN 10:
0133281140
ISBN 13:
978-0-13328-114-9
Chapter 9 - Quadratic Functions and Equations - 9-7 Linear Quadratic, and Exponential Models - Practice and Problem-Solving Exercises - Page 594: 31
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