Algebra 1: Common Core (15th Edition)

$(2x-1)(5x+2)$ are the factors of $10x^2-x-2$
We are given: $10x^2-x-2$ $=10x^2-5x+4x-2$ $=5x(2x-1)+2(2x-1)$ $=(2x-1)(5x+2)$ $(2x-1)(5x+2)$ are the factors of $10x^2-x-2$