Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 9 - Quadratic Functions and Equations - 9-2 Quadratic Functions - Practice and Problem-Solving Exercises: 31

Answer

50 dollars per phone

Work Step by Step

Allow x to be the number of additional phones that are sold. R = (price per phone)(number of phones sold) number of phones sold = 500 +20x price per phone = 75-x Multiply (500+ 20x)(75-x) together to get: R = 37500 +1000x -20x^2 Then, using the following equation, use the axis of symmetry formula to find the x coordinate that maximizes the revenue: x = -b/2a simplifies to: x= -1000/2(-20) simplifies to: x= 25 Once you have the value of x, plug it back into the equation 75 - x, which represents the price per phone. 75-25 =50 Therefore, the price should be 50 dollars per phone.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.