Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 9 - Quadratic Functions and Equations - 9-2 Quadratic Functions - Practice and Problem-Solving Exercises - Page 557: 25


See the graph

Work Step by Step

$f(x)=2x^2-6x+1$ Find the axis of symmetry and the coordinates of the vertex. $x=\frac{-b}{2a}=\frac{-(-6)}{2.2}=\frac{3}{2}$ The axis of symmetry is $x=\frac{3}{2}$. So the x-coordinate of the vertex is $\frac{3}{2}$. Substitute $\frac{3}{2}$ for x to find the y-coordinate of the vertex. $y=2(\frac{3}{2})^2-6(\frac{3}{2})+1$ $=\frac{-7}{2}$ The vertex is $(\frac{3}{2},\frac{-7}{2})$ Find some other points for the graph. $(0,1)$ $(3,1)$ Graph the vertex and the points we found.
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