# Chapter 9 - Quadratic Functions and Equations - 9-2 Quadratic Functions - Practice and Problem-Solving Exercises - Page 556: 8

Axis of symmetry: x=2 Vertex: (2,13)

#### Work Step by Step

$$y=−3x^2+12x+1$$ The standard form for a quadratic equation is $$y=ax^2+bx+c$$ So a= -3, b= 12, and c= 1 Axis of symmetry: The formula for axis of symmetry is $$x=−b/2a$$ $$x=−(12)/2(−3)$$ $$x=−12−6$$ $$x=2$$ Vertex: Plug in the x value of the axis of symmetry to find the y value of the vertex. $$y=−3^x2+12x+1$$ $$y=−3(2)^2+12(2)+1$$ $$y= -12 + 24 + 1$$ $$y= 13$$ The vertex is (2,13)

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