## Algebra 1: Common Core (15th Edition)

Axis of Symmetry => $x = \frac{3}{10}$ Vertex=> $(\frac{3}{10}, \frac{49}{20})$
Axis of Symmetry: $x= \frac{-b}{2a}$ $x= \frac{-(3)}{2(-5)}$ $x= \frac{-3}{-10}$ $x= \frac{3}{10}$ Finding y: $y = -5x^2 +3x+2$ *Replace the x with the axis of symmetry value* $y = -5(\frac{3}{10})^2 +3(\frac{3}{10})+2$ $y = -5(\frac{9}{100}) +3(\frac{3}{10})+2$ $y = -\frac{45}{100} +\frac{9}{10}+2$ $y = \frac{49}{20}$