# Chapter 9 - Quadratic Functions and Equations - 9-2 Quadratic Functions - Lesson Check - Page 556: 2

See the graph

#### Work Step by Step

$y=-2x^2-8x-7$ Find the axis of symmetry and the coordinates of the vertex. $x=\frac{-b}{2a}=\frac{-(-8)}{2.(-2)}=-2$ The axis of symmetry is $x = -2$. So the x-coordinate of the vertex is -2. Substitute -2 for x to find the y-coordinate of the vertex. $y=-2(-2)^2-8(-2)-7$ $y=-8+16-7$ $y=1$ The vertex is $(-2,1)$ Find two other points on the graph. $(0,-7)$ $(1,-17)$ Graph the vertex and the points we found.

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