#### Answer

See the graph

#### Work Step by Step

$y=x^2-4x+1$
Find the axis of symmetry and the coordinates of the vertex.
$x=\frac{-b}{2a}=\frac{-(-4)}{2.1}=2$
The axis of symmetry is $x = 2$. So the x-coordinate of the vertex is 2.
Substitute 2 for x to find the y-coordinate of the vertex.
$y=x^2-4x+1$
$y=2^2-4(2)+1$
$y=-3$
The vertex is $(2,-3)$
Find two other points on the graph.
$(0,1)$
$(1,-2)$
Graph the vertex and the points we found.