## Algebra 1: Common Core (15th Edition)

$y=x^2-4x+1$ Find the axis of symmetry and the coordinates of the vertex. $x=\frac{-b}{2a}=\frac{-(-4)}{2.1}=2$ The axis of symmetry is $x = 2$. So the x-coordinate of the vertex is 2. Substitute 2 for x to find the y-coordinate of the vertex. $y=x^2-4x+1$ $y=2^2-4(2)+1$ $y=-3$ The vertex is $(2,-3)$ Find two other points on the graph. $(0,1)$ $(1,-2)$ Graph the vertex and the points we found.