Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 8 - Polynomials and Factoring - 8-6 Factoring ax2+bx+c - Practice and Problem-Solving Exercises - Page 522: 50

Answer

$54h\left( {2g - 1} \right)\left( {g - 1} \right)$

Work Step by Step

Factor out $54h$ $$54h\left( {2{g^2} - 3g + 1} \right)$$ Factor the expression inside parentheses and distribute. $$\begin{array}{l}54h\left( {2{g^2} - 2g - g + 1} \right)\\54h\left[ {2g\left( {g - 1} \right) - 1\left( {g - 1} \right)} \right]\\54h\left( {2g - 1} \right)\left( {g - 1} \right)\end{array}$$ Therefore, the factored from of the given expression is $54h\left( {2g - 1} \right)\left( {g - 1} \right)$.
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