Answer
The answer is $(7y-4)(3y+12)$.
Work Step by Step
1. $3(7y^{2}+24y-16)$
2. $3(7y^{2}+28y-4y-16)$
3. $3[7y(y+4)-4(y+4)]$
4. $3(7y-4)(y+4)$
5. $(7y-4)(3y+12)$
Algebra 1: Common Core (15th Edition)
by Charles, Randall I.
Published by
Prentice Hall
ISBN 10:
0133281140
ISBN 13:
978-0-13328-114-9
Chapter 8 - Polynomials and Factoring - 8-6 Factoring ax2+bx+c - Practice and Problem-Solving Exercises - Page 522: 42
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