Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 8 - Polynomials and Factoring - 8-4 Multiplying Soecial Cases - Practice and Problem-Solving Exercises - Page 507: 16



Work Step by Step

You can use the formula: $(a-b)^{2}$=$a^{2}$-2ab+$b^{2}$ Substituting the values in this formula and simplifying: $(4x-6)^{2}$=$(4x)^{2}$-2(4x)(6)+$(-6)^{2}$=16$x^{2}$-48x+36
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