## Algebra 1: Common Core (15th Edition)

$h^{2}$+4h+4
The formula to be used is: $(a+b)^{2}$=$a^{2}$+2ab+$b^{2}$ We substitute the values and simplify: $(h+2)^{2}$= $h^{2}+(2)(h)(2)+2^{2}$= $h^{2}+4h+4$