## Algebra 1: Common Core (15th Edition)

In the first step, the error is in distributing the products (one term is missing, there should be four). result: $3x^{2}-2x-8$
In the first step, the error is in distributing the products (one term is missing, there should be four). It should be $(x-2)(3x+4)$ $=x(3x)+x(4)-2(3x)-2(4)$ $=3x^{2}+4x-6x-8$ ...add like terms. =$3x^{2}-2x-8$