# Chapter 8 - Polynomials and Factoring - 8-3 Multiplying Binomials - Practice and Problem-Solving Exercises - Page 502: 42

In the first step, the error is in distributing the products (one term is missing, there should be four). result: $3x^{2}-2x-8$

#### Work Step by Step

In the first step, the error is in distributing the products (one term is missing, there should be four). It should be $(x-2)(3x+4)$ $=x(3x)+x(4)-2(3x)-2(4)$ $=3x^{2}+4x-6x-8$ ...add like terms. =$3x^{2}-2x-8$

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