Chapter 8 - Polynomials and Factoring - 8-3 Multiplying Binomials - Practice and Problem-Solving Exercises - Page 502: 34

$6g^{3}+11g^{2}-31g+14$

$\left[\begin{array}{lllllllll} & 3g^{2} & -5g & +2 & & & & & \\ & & 2g & +7 & & & & & \\ -- & -- & -- & -- & & & & & \\ & 21g^{2} & -35g & +14 & \text{multiply by }+7 & & & & \\ 6g^{3} & -10g^{2} & 4g & & \text{multiply by } 2g & & & & \\ -- & -- & -- & -- & \text{add like terms } & & & & \\ 6g^{3} & 11g^{2} & -31g & +14 & & & & & \end{array}\right]$ Answer: $6g^{3}+11g^{2}-31g+14$