## Algebra 1: Common Core (15th Edition)

$\frac{1}{a}$
You are given $a^{2}$$b^{0}(a^{-3}). a^{2}$$a^{-3}$ -any number raised to 0 equals 1 so $b^{0}$=1- $a^{2+-3}$ -add the exponents since they have the same base- $a^{-1}$ -use the exponent rule $x^{-y}$=$\frac{1}{x^y}$- The simplified expression is $\frac{1}{a}$