## Algebra 1: Common Core (15th Edition)

You are given $f(x)=$ $0.1^{x}$. Plug in the values $-2,-1,0,1,2$ for the X-variable: $f(-2)=$ $0.1^{-2}={\dfrac{1}{0.01}}=100$ $f(-1)=$ $0.1^{-1}={\dfrac{1}{0.1}}=10$ $f(0)=$ $0.1^{0}=1$ $f(1)=$ $0.1^{1}=0.1$ $f(2)=$ $0.1^{2}=0.01$