## Algebra 1: Common Core (15th Edition)

You have f(x)=75 $\times$ $4^{x}$.Where it represents the number of foxes after 15-year periods. Plug in x=3 since there are 3 15-year periods in 45 years. f(3)=75 $\times$ $4^{3}$ f(3)=4800 After 45 years, there would be 4800 foxes.