## Algebra 1: Common Core (15th Edition)

$1.499$ mm $\lt d \lt 1.501$ mm
$10^{-3}=\displaystyle \frac{1}{10^{3}}=\frac{1}{1000}=0.001$ So, an acceptable diameter $d$ is one between $(1.500-0.001)$ mm = $1.499$ mm and $(1.500+0.001)$ mm = $1.501$ mm $1.499$ mm $\lt d \lt 1.501$ mm