Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 7 - Exponents and Exponential Functions - 7-1 Zero and Negative Exponents - Practice and Problem-Solving Exercises - Page 423: 68


The answer is 141$m^{-2}$, or $\frac{141}{m^{2}}$

Work Step by Step

To solve the expression: $\frac{6}{m^{2}}$ + $\frac{5m^{-2}}{3^{-3}}$ = $\frac{6}{m^{2}}$ + $\frac{5\times3^{3}}{m^{2}}$ = $\frac{6+(5\times27)}{m^{2}}$ = $\frac{6+135}{m^{2}}$ = $\frac{141}{m^{2}}$ or 141$m^{-2}$
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