## Algebra 1: Common Core (15th Edition)

Published by Prentice Hall

# Chapter 7 - Exponents and Exponential Functions - 7-1 Zero and Negative Exponents - Practice and Problem-Solving Exercises - Page 422: 57

#### Answer

The expression is 4g$h^{-3}$

#### Work Step by Step

The expression $\frac{4g}{h^{3}}$ can be written with all the variables in the numerator; as we bring the h to the numerator, the sign of the exponent changes from positive to negative. $\frac{4g}{h^{3}}$ = 4g$h^{-3}$

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