## Algebra 1: Common Core (15th Edition)

The answer is -$\frac{27}{400}$
The expression $2^{-4}$$\times$$r^{3}$$\times$$s^{-2}$ can be simplified to $\frac{r^{3}}{2^{4}\times(s)^{2}}$ So, to solve this question, we can plug in r=-3 and s=5 $\frac{r^{3}}{2^{4}\times(s)^{2}}$ = $\frac{(-3)^{3}}{2^{4}\times(5)^{2}}$ = $\frac{-27}{16\times25}$ = $\frac{-27}{400}$