Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 7 - Exponents and Exponential Functions - 7-1 Zero and Negative Exponents - Practice and Problem-Solving Exercises - Page 422: 44


The answer is -$\frac{27}{400}$

Work Step by Step

The expression $2^{-4}$$\times$$r^{3}$$\times$$s^{-2}$ can be simplified to $\frac{r^{3}}{2^{4}\times(s)^{2}}$ So, to solve this question, we can plug in r=-3 and s=5 $\frac{r^{3}}{2^{4}\times(s)^{2}}$ = $\frac{(-3)^{3}}{2^{4}\times(5)^{2}}$ = $\frac{-27}{16\times25}$ = $\frac{-27}{400}$
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