## Algebra 1: Common Core (15th Edition)

Recall, anything raised to the zeroth power is 1, and $a^{-n}= \frac{1}{a^{n}}$. Thus, we simplify this expression and solve: $2(a)^{-4}b^{0}=\frac{2}{(a)^{4}}=2/(2^{4})=1/8$