Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 7 - Exponents and Exponential Functions - 7-1 Zero and Negative Exponents - Lesson Check: 5

Answer

-2

Work Step by Step

Recall the equation: $a^{-n}= \frac{1}{a^{n}}$. Thus, we simplify this expression and solve: $a^{3}b^{-1}=\frac{a^{3}}{b}$ We now plug in 2 for a and -4 for b to obtain: $\frac{2^{3}}{-4}=8/-4=-2$
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