Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 6 - Systems of Equations and Inequalities - Get Ready!: 4

Answer

$c=3$

Work Step by Step

We start with the given equation: $\frac{1}{2}(6c-4)=4+c$ We multiply the entire equation by $2$ to clear the fraction: $$2\left[\frac{1}{2}(6c-4)=4+c\right]$$$$6c-4=8+2c$$ We add $4-2c$ to both sides of the equation: $6c-4+4-2c=8+2c+4-2c$ We combine like terms: $4c=12$ We divide by $4$ on each side of the equation: $$\frac{4c}{4}=\frac{12}{4}$$$$c=3$$
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