## Algebra 1: Common Core (15th Edition)

a. $2x-1$ b. $\frac{1}{2}(2x-1)\times y$ where y is the height c. $248$
The height of the triangle is 1 cm less than twice the length of the base where x= the length of the base a. the expression would be $2x-1$ b. $\frac{1}{2}(2x-1)\times y$ where y is the height c. $x=16$ so plug that into $2x-1$ to find the height $2(16)-1$ so the height would be $31$ Now multiply the base and height $16\times31$ Since it is a triangle you must divide by 2 so the answer would be $248$