#### Answer

$x$ $\leq$ $1$
$y$ $\lt$ $\dfrac{-3}{2}x+3$

#### Work Step by Step

The equation is $x$ $\leq$ $1$ because $x=1$ and the left side of the line is shaded.
The points $(0,3)$ and $(2,0)$. Find the slope:
$m=\dfrac{3-0}{0-2}$
$m={-\dfrac{3}{2}}$
The slope equation is $y=mx+b$
$y=mx+b$
$0=-{\dfrac{3}{3}}(2)+b$
$0=-3+b$
$3=b$
The equation is $y$ $\lt$ $\dfrac{-3}{2}x+3$ because $(0,0)$ is not included in the solution area.