Algebra 1: Common Core (15th Edition)

$x$ $\leq$ $1$ $y$ $\lt$ $\dfrac{-3}{2}x+3$
The equation is $x$ $\leq$ $1$ because $x=1$ and the left side of the line is shaded. The points $(0,3)$ and $(2,0)$. Find the slope: $m=\dfrac{3-0}{0-2}$ $m={-\dfrac{3}{2}}$ The slope equation is $y=mx+b$ $y=mx+b$ $0=-{\dfrac{3}{3}}(2)+b$ $0=-3+b$ $3=b$ The equation is $y$ $\lt$ $\dfrac{-3}{2}x+3$ because $(0,0)$ is not included in the solution area.