#### Answer

$y$ $\leq$ $x+2$
$y$ $\lt$ $-\dfrac{1}{3}x$

#### Work Step by Step

The points $(0,2)$ and $(1,3)$.Find the slope:
$m=\dfrac{3-2}{1-0}$
$m=1$
The slope equation:
$y=mx+b$
$2=1(0)+b$
$2=0+b$
$2=b$
The equation is $y$ $\leq$ $x+2$ because $(0,0)$ is not included in the solution area.
The points $(0,0)$ and $(3,-1)$.Find the slope:
$m=\dfrac{0--1}{0-3}$
$m={-\dfrac{1}{3}}$
The slope equation is $y=mx+b$
$y=mx+b$
$0=-{\dfrac{1}{3}}(0)+b$
$0=0+b$
$0=b$
The equation is $y$ $\lt$ $-\dfrac{1}{3}x$ because $(1,1)$ is not included in the solution area.