Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 6 - Systems of Equations and Inequalities - 6-4 Applications of Linear Systems - Practice and Problem-Solving Exercises - Page 391: 14

Answer

$x=2$ $ y=-1$

Work Step by Step

$4x+5y=3$ $3x-2y=8$ Solve the second equation to find $y$ $3x-2y=8$ $2y=3x-8$ $y=\frac{3}{2}x-4$ Substitute $y=\frac{3}{2}x-4$ for y in the first equation and solve for x. $4x+5(\frac{3}{2}x-4)=3$ $4x+\frac{15}{2}x-20=3$ $\frac{23}{2}x=23$ $x=2$ $\rightarrow y=-1$
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