Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 6 - Systems of Equations and Inequalities - 6-3 Solving Systems Using Elimination - Practice and Problem-Solving Exercises - Page 382: 23


One solution (2,0)

Work Step by Step

You have the equations:5x-3y=10 and 10x+6y=20. Multiply the first equation by 2 so you can eliminate the y variable: 2(5x-3y=10) 10x-6y=20 Eliminate the equations by combining them: 10x+6y=20 10x-6y=20 -combine the equations- 20x=40 -divide both sides by 20- x=2 Plug in x=2 into one of the equations: 10(2)+6y=20 -distribute- 20+6y=20 -subtract 20 from both sides- 6y=0 -divide both sides by 6- y=0 Check the solutions by plugging in x=2 and y=0 into one of the equations: 5(2)-3(0)=10 10-0=10 10=10 The one solution is (2,0)
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