## Algebra 1: Common Core (15th Edition)

$y-10=5(x-2)$
We first find the slope. The equation for slope is: $\frac{y_{2}-y_{1}}{x_{2}-x_{1}}$. Thus, we obtain: $\frac{10-(-5)}{2-(-1)}=\frac{15}{3}=5$ Recall, the equation for point slope form is the following: $y- y_{1}=m(x - x_{1})$, where $(x_{1} , y_{1})$ is a point on the line and m is the slope of the line. Thus, we plug 2 in for $x_{1}$, 10 in for $y_{1}$, and 5 in for m to obtain the answer: $y-10=5(x-2)$