Chapter 5 - Linear Functions - Mid-Chapter Quiz - Page 321: 18

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We are given $y+3=\frac{1}{2}(x+2)$ $\rightarrow y=\frac{1}{2}x-2$ Find the y-intercept by setting $x$ to $0$. When $x$ is $0$, $y=-2$, so the y-intercept is $(0,−2)$. Plot it. Find the x-intercept by setting $y$ to $0$. When $y$ is $0$, $x=4$, so the x-intercept is $(4,0)$. Plot it. Connect these two points, and you get a line.