## Algebra 1: Common Core (15th Edition)

y-1=$\frac{1}{3}$(x-5)
You have the point (5,1) and the slope is $\frac{1}{3}$.The point-slope form is y-$y_{1}$=m(x-$x_{1}$).Plug in 5 for $x_{1}$,1 for $y_{1}$ and $\frac{1}{3}$ for m so the equation would be : y-1=$\frac{1}{3}$(x-5)