Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 5 - Linear Functions - Chapter Test - Page 357: 6

Answer

$x - 3y = 6$

Work Step by Step

To rewrite an equation in standard form, we use the following formula: $Ax + By = C$ For the equation $y + 4 = \frac{1}{3}(x + 6)$, we first distribute the terms: $y + 4 = \frac{1}{3}x + \frac{1}{3}(6)$ Multiply to simplify: $y + 4 = \frac{1}{3}x + \frac{6}{3}$ Simplify the fraction by dividing both the numerator and denominator by their greatest common factor, which is $3$: $y + 4 = \frac{1}{3}x + 2$ Subtract $4$ from each side of the equation to isolate constants on one side of the equation: $y = \frac{1}{3}x + 2 - 4$ Subtract to simplify: $y = \frac{1}{3}x - 2$ Move the $x$ term to the other side of the equation by subtracting $\frac{1}{3}x$ from both sides of the equation: $-\frac{1}{3}x + y = -2$ Divide both sides by $-1$ to make the $x$ term positive: $\frac{1}{3}x - y = 2$ To make all values integers, we multiply everything by the denominator of the fraction, which will make the fraction an integer: $3(\frac{1}{3}x - y) = 3(2)$ Distribute terms first, according to order of operations: $\frac{3}{3}x - 3y = 6$ Simplify the fraction by dividing both the numerator and denominator by their greatest common factor, which is $3$: $x - 3y = 6$
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