Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 5 - Linear Functions - 5-6 Parallel and Perpendicular Lines - Practice and Problem-Solving Exercises - Page 334: 22



Work Step by Step

You are given $(-3,2)$ and a perpendicular equation of $y=\dfrac{1}{2}x-\dfrac{7}{2}$ when put in standard form. Since the lines are perpendicular, the slope of the new equation is an opposite reciprocal so the slope $\dfrac{1}{2}$ would become $-2$. Plug in the points to find B: $y=-2x+b$ $2=-2(3)+b$ $2=6+b$ $b=-4$ The new equation is $y=-2x-4$
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