Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 5 - Linear Functions - 5-6 Parallel and Perpendicular Lines - Practice and Problem-Solving Exercises - Page 334: 21


The new equation is $y=-\dfrac{1}{5}x-\dfrac{9}{5}$

Work Step by Step

You are given $(1,-2)$ and a perpendicular equation of $y=5x+4$. Since the lines are perpendicular, the slope of the new equation is an opposite reciprocal so the slope $5$ would become $-\dfrac{1}{5}$. Plug in the points to find B: $y=-\dfrac{1}{5}x+b$ $-2=-\dfrac{1}{5}+b$ $b=-\dfrac{9}{5}$ The new equation is $y=-\dfrac{1}{5}x-\dfrac{9}{5}$
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