## Algebra 1: Common Core (15th Edition)

1. The second term is 16 2. The third term is 19 3. The fourth term is 22 4. The explicit formula is $A(n)=13+3(n-1)$
We are given: $A(1)=13$ $A(n)=A(n-1)+3$ 1. The second term is $A(2)=A(2-1) +3 = A(1)+3 =13 +3= 16$ 2. The third term is $A(3)=A(3-1)+3 = A(2)+3 = 16+3= 19$ 3. The fourth term is $A(4)=A(4-1)+3 = A(3)+3 = 19 +3 = 22$ 4. The explicit formula is $A(n)=13+3(n-1)$