## Algebra 1: Common Core (15th Edition)

$m-\frac{1}{2}\lt\frac{3}{8};m\lt\frac{7}{8}$ Add $\frac{1}{2}$ to both sides $m-\frac{1}{2}+\frac{1}{2}\lt\frac{3}{8}+\frac{1}{2};m\lt\frac{7}{8}$ Mulitply 1/2 by 4/4 to make the denominator 8 $m\lt\frac{3}{8}+\frac{4}{8}$ $m\lt\frac{7}{8};m\lt\frac{7}{8}$ equivalent