## Algebra 1: Common Core (15th Edition)

$-7\frac{1}{2}\leq n$
$6\geq-\frac{4}{5}n$ Multiply both sides by 5 $6(5)\geq-\frac{4}{5}n(5)$ $30\geq-4n$ Divide both sides by -4, reverse the sign $\frac{30}{-4}\geq\frac{-4n}{-4}$ $\frac{15}{-2}\leq n$ or $-7\frac{1}{2}\leq n$ $n\geq\frac{15}{-2}$ or $n\geq-7\frac{1}{2}$