## Algebra 1: Common Core (15th Edition)

$k\lt12$
$8\gt\frac{2}{3}k$ Mulitply both sides by $\frac{3}{2}$ $\frac{3}{2}\times8\gt\frac{2}{3}k\times\frac{3}{2}$ $\frac{24}{2}\gt k$ $12\gt k$ Let's check let $k=9$ $8\gt\frac{2}{3}(9)$ $8\gt\frac{18}{3}$ $8\gt6$