## Algebra 1: Common Core (15th Edition)

$x\geq-3$
$-7\leq\frac{7}{3}x$ Multiply both sides by $\frac{3}{7}$. $-7\times\frac{3}{7}\leq\frac{7}{3}x\times\frac{3}{7}$ Simplify: $-\frac{3}{1}\leq x$ $-3\leq x$ Let's check: Let x=5 $-7\leq\frac{7}{3}(5)$ $-7\leq\frac{35}{3}$ The statement is true