Algebra 1: Common Core (15th Edition)

$a\geq-1$
$\frac{1}{4}+a\geq-\frac{3}{4}$ To get a on one side by itself, subtract $-\frac{1}{4}$: $\frac{1}{4}+a-\frac{1}{4}\ge \:-\frac{3}{4}-\frac{1}{4}$ Simplfy: $a\geq-\frac{3}{4}-\frac{1}{4}$ apply rule:$\frac{a}{c}\pm \frac{b}{c}=\frac{a\pm \:b}{c}$: $a\geq\frac{-3-1}{4}$ $a\geq\frac{-4}{4}$ $a\geq-1$ Let's check: $a=-1$ $-1\geq-1$ $true$ $a=2$ $2\geq-1$ $true$