Answer
$\frac{k}{9}\gt \frac{1}{3}$
Work Step by Step
To find the inequality, the quotient of $k$ and $9$ is greater than $\frac{1}{3}$, arrange your inequality in the order stated:
$\frac{k}{9}$ greater than $\frac{1}{3}$
The greater than sign is $\gt$. Add this in between $\frac{k}{9}$ and $\frac{1}{3}$.
$\frac{k}{9}\gt \frac{1}{3}$
