## Algebra 1: Common Core (15th Edition)

$\frac{k}{9}\gt \frac{1}{3}$
To find the inequality, the quotient of $k$ and $9$ is greater than $\frac{1}{3}$, arrange your inequality in the order stated: $\frac{k}{9}$ greater than $\frac{1}{3}$ The greater than sign is $\gt$. Add this in between $\frac{k}{9}$ and $\frac{1}{3}$. $\frac{k}{9}\gt \frac{1}{3}$