## Algebra 1: Common Core (15th Edition)

$c=28$
We need to get the c alone. Thus, we cancel out the subtraction by adding 4 on both sides. This leaves us with the equation $c/3 +c/6 =14$. We now need a common denominator for c, so we multiply c/3 by 2/2 to get that $2c/6 +c/6 =14$. We combine like terms to get that $3c/6=14$, which simplifies to $c/2=14$. In order to cancel out division, we use multiplication, so we multiply both sides by 2 to get that $c=28$. We plug 28 in for c and confirm that our answer is, indeed, correct.