Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 2 - Solving Equations - Chapter Review - Page 153: 20



Work Step by Step

We need to get the c alone. Thus, we cancel out the subtraction by adding 4 on both sides. This leaves us with the equation $c/3 +c/6 =14$. We now need a common denominator for c, so we multiply c/3 by 2/2 to get that $2c/6 +c/6 =14$. We combine like terms to get that $3c/6=14$, which simplifies to $c/2=14$. In order to cancel out division, we use multiplication, so we multiply both sides by 2 to get that $c=28$. We plug 28 in for c and confirm that our answer is, indeed, correct.
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