Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 2 - Solving Equations - 2-7 Solving Proportions - Practice and Problem-Solving Exercises - Page 129: 57



Work Step by Step

$\frac{5x}{x^{3}+5}=\frac{5}{x^{2}-7}$ Expand: $5x^3-35x=5x^3+25$ Subtract $5x^3$ from both sides: $5x^{3}-35x-5x^{3}=5x^{3}+25-5x^3$ Simplify: $-35x=25$ Divide both sides by -35: $\frac{-35x}{-35}=\frac{25}{-35}$ Simplify: $x=-\frac{5}{7}$
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