## Algebra 1: Common Core (15th Edition)

$w^2+3/2w+2=w/2$ cross multiply $2(w^2+3)=w(2w+2)$ distributive property $2w^2+6=2w^2+2w subtract 2w^2$ from each side $2w^2+6−2w^2=2w^2+2w−2w^2$ combine like terms 6=2w divide both sides by 2 6÷2=2w÷2 simplify 3=w