Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 2 - Solving Equations - 2-7 Solving Proportions - Practice and Problem-Solving Exercises - Page 129: 56



Work Step by Step

$w^2+3/2w+2=w/2$ cross multiply $2(w^2+3)=w(2w+2)$ distributive property $2w^2+6=2w^2+2w subtract 2w^2$ from each side $2w^2+6−2w^2=2w^2+2w−2w^2$ combine like terms 6=2w divide both sides by 2 6÷2=2w÷2 simplify 3=w
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