## Algebra 1: Common Core (15th Edition)

We first follow the instructions to plug 3 in for b and 7 in for c. We then use order of operations, first multiplying 3 times 3 since that is in parenthesis, then raising 9 to the second power, and then multiplying by 7 to get the answer. $(3\times 3)^{2} \times 7 \\\\ =9^{2} \times 7 \\\\ =81\times 7 \\\\ =567$