Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 2 - Solving Equations - 2-5 Literal Equations and Formulas - Practice and Problem-Solving Exercises - Page 114: 66

Answer

$\frac{7}{45}$

Work Step by Step

$\frac{21}{81}\times\frac{63}{105}$ Simplify each fraction. $\frac{21}{81}=\frac{7}{27}$, $\frac{63}{105}=\frac{3}{5}$ Use cross-simplification to further reduce before multiplying. $\frac{7}{27}\times\frac{3}{5} = \frac{7}{9}\times\frac{1}{5}$ Multiply. $\frac{7}{9}\times\frac{1}{5} = \frac{7}{45}$
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