## Algebra 1: Common Core (15th Edition)

$3x-8=5$
(You are asked to correct the solution given. When distributing 8 on the left side over the 3x/8 -1, you get 3x - 8 not 3x - 1. The 8 must be distributed over both values in the parentheses.) $\frac{3x}{8}-1=\frac{5}{8}$ $8(\frac{3x}{8}-1)=(\frac{5}{8})8$ $3x-8=5$